Question

Certain car can accelerate from rest to the speed v in t seconds. if the power output of the car remains constant, (a) how long does it take for the car to accelerate from v to 2v? (b) how fast is the car moving at 2t seconds after starting

Answer 1

(a) time taken for the car to accelerate from v to 2v = t = $\frac{2V-V}{a}$

(b) velocity of the car moving at 2t seconds = ΔV = 2at

(a) we know that,

a=$\frac{V_{F}-V_{0} }{t}$

where, $V_{F}$ is the final velocity

$V_{0}$ is the initial velocity

a = acceleration

t = time

Time taken to accelerate from V to 2V:

t = $\frac{2V-V}{a}$

(b) We know that,

a=$\frac{V_{F}-V_{0} }{t}$

where, $V_{F}$ is the final velocity

$V_{0}$ is the initial velocity

a = acceleration

t = time

how fast is the car moving at 2t seconds after starting,

we can represent $V_{F}$ - $V_{0}$ = ΔV

at time = t= 2t, it becomes

a=$\frac{V_{F}-V_{0} }{t}$ = a = ΔV/2t

t= ΔV/2a

ΔV = 2at

What is acceleration?

Rate of change of velocity with time, both in terms of speed and direction is known as acceleration.

What is speed?

• the rate at which an object's location changes in any direction.
• The distance traveled in relation to the time it took to travel that distance is how speed is defined.
• Since speed simply has a direction and no magnitude, it is a scalar quantity.

To learn more about acceleration visit:

https://brainly.com/question/12550364

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