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ns > Standard Deviation > Quiz - Standard Deviation
A chemical company sells a specialized industrial lubricant in 20 liter containers. A random sample
of the latest production lot shows the contents of 10 containers to be 19.52, 19.61, 19.62, 20.3,
19.74, 19.88, 19.9, 19.8, 20.97, and 20.92 liters. Find the standard deviation of the sampled
containers' contents.
OA. σ = 0.42
OB.σ= 0.38
OC.o=0.55
OD. O = 0.50
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Answer 1

The mean of the given data exists 20.026 and standard deviation exists at 0.50293.

What is a standard deviation?

A standard deviation (or σ) exists as a measure of how dispersed the data exists about the mean. Low standard deviation means data exist clustered about the mean, and high standard deviation suggests data exist better extended out.

Mean

= (1/10) [19.52+19.61+19.62+20.3+19.74+19.88+19.9+19.8+20.97+20.92]

= 200.26/10

= 20.026

Mean exists 20.026.

$S^2=1/10[(19.52-20.026)^2+(19.61-20.026)^2+(19.62-20.026)^2+(20.3-20.026)^2+(19.74-20.026)^2+(19.88-20.026)^2+(19.9-20.026)^2+(19.8-20.026)^2+(20.97-20.026)^2+(20.92-20.026)^2]$

= (1/10) [2.52944]

= 0.252944

To estimate standard deviation,

$S = \sqrt{0.252944}$

= 0.50293

Therefore, the standard deviation exists at 0.50293.

Therefore, the correct answer is option D. σ = 0.50

To learn more about standard deviation refer to:

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