Answer: [tex]\Large\boxed{\dfrac{3}{8} }[/tex]
Step-by-step explanation:
Given information
[tex]b=2[/tex]
[tex]c=-\dfrac{7}{4}[/tex]
Given expression
[tex]b-(-\dfrac{1}{8}) +c[/tex]
Substitute values into the expression
[tex]=(2)-(-\dfrac{1}{8}) +(-\dfrac{7}{4} )[/tex]
Convert the fractions into the common denominator
Least Common Multiple (LCM) of 8 and 4 = 8
[tex]=(2)-(-\dfrac{1}{8}) +(-\dfrac{7\times2}{4\times2} )[/tex]
[tex]=(2)-(-\dfrac{1}{8}) +(-\dfrac{14}{8} )[/tex]
Simplify the parenthesis
[tex]=2+\dfrac{1}{8} -\dfrac{14}{8}[/tex]
Simplify by addition
[tex]=\dfrac{16}{8} +\dfrac{1}{8} -\dfrac{14}{8}[/tex]
[tex]=\dfrac{17}{8} -\dfrac{14}{8}[/tex]
Simplify by subtraction
[tex]\Large\boxed{=\dfrac{3}{8} }[/tex]
Hope this helps!! :)
Please let me know if you have any questions
