Question

Find the dy/dx using implicit differentiation
x³-3x²y+2xy² = 12

Answer 1

The dy/dx of equation  $x^{3} -3x^{2} y+2xy^{2} =12$ is $(6xy-3x^{2} -2y^{2} )/(4xy-3x^{2})$.

Given an equation $x^{3} -3x^{2} y+2xy^{2} =12$.

We are required to find dy/dx of the equation.

Equation is like a relationship between two or more variables that are expressed in equal to form. Equations of two variables look like ax+by=c.

Differentiation is basically finding the change in variables.

It may be linear equation, quadratic equation,cubic equation or many more depending on the power of the variable present in the equation.

Equation:$x^{3} -3x^{2} y+2xy^{2} =12$

Differentiating with respect to x.

3$x^{2}$-3($x^{2}$*dy/dx+y*2x)+2(x*2y*dy/dx+$y^{2}$)=0

3$x^{2} -3x^{2} dy/dx-6xy+4xy dy/dx+2y^{2}$=0

Taking dy/dx at one side and take the other part to other end.

$-3x^{2} dy/dx+4xy dy/dx$=$6xy-3x^{2} -2y^{2}$

dy/dx=$(6xy-3x^{2} -2y^{2})/(4xy-3x^{2} )$

Hence the dy/dx of equation  $x^{3} -3x^{2} y+2xy^{2} =12$ is $(6xy-3x^{2} -2y^{2} )/(4xy-3x^{2})$.

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