The volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.
The volume of a given amount of gas can be calculated by using the combined gas law formula as follows;
P1V1/T1 = P2V2/T2
Where;
According to this question, 1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm.
However, half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The volume in the final system can be calculated as follows:
2 × 12.3/300 = 2 × V2/900
0.082 = 2V2/900
73.8 = 2V2
V2 = 73.8 ÷ 2
V2 = 36.9L
Therefore, the volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.
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