Question

What would the potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions? [h ]=0. 84 mh2=2. 2 atm=298 k

Answer 1

The potential of a standard hydrogen electrode (s. h. e. ) be under the given conditions is - 0.029 V

Calculation ,

Formula used :

$E_{cell}$ = $E_{cell}$ ° - 0.059/n ㏒$H_{2}$/ $[H^{+}]^{2}$

As we know that ,

[$H^{+}$] = 0. 84 M

$P_{H_{2}$ = 2. 2 atm

Temperature ( T ) = 298  K

From reaction at electrode number of electrons involve ( n ) = 1

Standard electrode potential of  standard hydrogen electrode $E_{cell}$ ° = 0

Putting the value of all data in equation ( i ) , we get

$E_{cell}$ = 0  - 0.059/1 ㏒2. 2 / $(0. 84)^{2}$ =  - 0.059 ㏒3.14 =  - 0.059×0.497

$E_{cell}$ = - 0.029 V

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