Respuesta :
The actual theoretically yield from this reaction is 86.5 grams.
What is theoretically yield?
- Theoretical yield is the quantity of a product obtained from the complete conversion of the limiting reactant in a chemical reaction.
- It is the amount of product resulting from a perfect (theoretical) chemical reaction, and thus not the same as the amount you'll actually get from a reaction in the lab.
∵ The percentage yield = (actual yield/theoretical yield) * 100.
To calculate the theoretical yield from the balanced reaction:
CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O,
It is clear that 1 mole of CaCO₃ reacts with 2 mole of HCl to produce 1 mole of CaCl₂, 1 mole of CO₂, and 1 mole H₂O.
to calculate the no. of moles of 95.0 g CaCO₃
n = mass/molar mass = (95.0 g)/(100.0869 g/mole) = 0.95 mol.
Using cross multiplication:
1 mole of CaCO₃ produce → 1 mole of CaCl₂, from stichiometry.
∴ 0.95 mole of CaCO₃ produce → 0.95 mole of CaCl₂.
∴ The mass of CaCl₂ (theoretical yield) = (no. of moles) * (molar mass) ⇒(0.95 mole)*(110.98 g/mole) = 105.34 g.
∵ The percentage yield = (actual yield/theoretical yield)*100.
The percentage yield = 82.15%, theoretical yield = 105.34 g.
∴ The actual yield of CaCl₂ = (The percentage yield)(theoretical yield)/100
= (82.15%)(105.34 g)/100 = 86.53 g ≅ 86.5 g.
So, the actual theoretically yield from this reaction is 86.5 grams.
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