Respuesta :
The molar concentration of the acid, HCl required for the reaction is 0.614 M
We'll begin by writing the balanced equation for the reaction. This is given below:
2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O
The mole ratio of the acid, HCl (nA) = 2
The mole ratio of the base, Ca(OH)₂ (nB) = 1
From the question given above, the following data were obtained:
Volume of acid, HCl (Va) = 50.6 mL
Volume of base, Ca(OH)₂ (Vb) = 45 mL
Molarity of base, Ca(OH)₂ (Mb) = 0.345 M
Molarity of acid, HCl (Ma) =?
MaVa / MbVb = nA/nB
(Ma × 50.6) / (0.345 × 45) = 2
(Ma × 50.6) / 15.525 = 2
Cross multiply
Ma × 50.6 = 15.525 × 2
Ma × 50.6 = 31.05
Divide both side by 50.6
Ma = 31.05 / 50.6
Ma = 0.614 M
Therefore, the molar concentration of the acid, HCl is 0.614 M
What is Molar Concentration?
Molar concentration, also known as molarity, is most commonly expressed in moles of solute per litre of solution. It is defined in broader applications as the amount of solute substance per unit volume of solution or per unit volume available to the species, represented by lowercase letters.
Learn more about Molar Concentration:
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