Current in the inductor, I = 100A
Given,
Magnetic potential energy stored, U= 30 joule
Inductance, L = 6.0 H
Therefore, current in the inductor, [tex]I^{2}[/tex]= (2×30×10^3) ÷ 6
= 2×5×10^3
= 10×10^3
[tex]I^{2}[/tex] = 10000
I = √10000
I = 100A
Concept:-
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