The distance from Sang to Jazmin is 101 yards.
From the discussion in the question, we can see that the positions of Sang and Jazmin can be construed to give a rectangle. We know that the rectangle is a four sided figure.
The diagonal is a line that is drawn from one side of the four sided figure to another. Hence we can be able to apply the Pythagoras theorem to obtain the distance from Sang to Jazmin.
From;
c^2 = a^2 + b^2
c = √a^2 + b^2
c = √(20)^2 + (99)^2
c = 101 yards.
Learn more about Pythagoras theorem:https://brainly.com/question/343682
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