Question

neeed help please pleasee

Answer 1

Answer:

Y = 2+- square root of 6

Step-by-step explanation:

Answer 2

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Lets solve ~

Let's calculate its discriminant ~

$\qquad \sf  \dashrightarrow \: {y}^{2} -4y - 2=0$

• a = 1

• b = -4

• c = -2

$\qquad \sf  \dashrightarrow \: discriminant = {b}^{2} - 4ac$

$\qquad \sf  \dashrightarrow \: d = (-4) {}^{2} - (4 \times 1\times - 2)$

$\qquad \sf  \dashrightarrow \: d = 16 - ( - 8)$

$\qquad \sf  \dashrightarrow \: d = 24$

$\qquad \sf  \dashrightarrow \: \sqrt {d }= 2 \sqrt{6}$

So, by quadratic formula :

$\qquad \sf  \dashrightarrow \: y= \dfrac{ - {b}^{} \pm \sqrt{d} }{2a}$

$\qquad \sf  \dashrightarrow \: y = \dfrac{ - {(-4)}^{} \pm 2\sqrt{6} }{2 ×1}$

$\qquad \sf  \dashrightarrow \: \:y=\pm \cfrac{2(2\pm\sqrt{6} }{2}$

$\qquad \sf  \dashrightarrow \: \:y= { 2+\sqrt{6}}{} \: \: and \: \: t = {2-\sqrt{6}}{}$