Question

please guys please pllease

Answer 1

Answer:

x= -3.936 and -0.064

Step-by-step explanation:

I simplified the equation to 40u^2 +16u + 1. Then I just graphed it and found that the zeroes were -3.936 and -0.064.

Answer 2

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

Let's calculate its discriminant :

$\qquad \sf  \dashrightarrow \: 4 {u}^{2} + 16u + 41 = 40$

$\qquad \sf  \dashrightarrow \: 4 {u}^{2} + 16u + 41 - 40 = 0$

$\qquad \sf  \dashrightarrow \: 4 {u}^{2} + 16u + 1 = 0$

Here, if we equate it with general equation,

• a = 4

• b = 16

• c = 1

$\qquad \sf  \dashrightarrow \: disciminant = {b}^{2} - 4ac$

$\qquad \sf  \dashrightarrow \: d = (16) {}^{2} - (4 \times 4 \times 1)$

$\qquad \sf  \dashrightarrow \: d = (16) {}^{2} - (16)$

$\qquad \sf  \dashrightarrow \: d = 16(16 - 1)$

$\qquad \sf  \dashrightarrow \: d = 16(15)$

$\qquad \sf  \dashrightarrow \: d = 240$

Now, since discriminant is positive ; it has two real roots ~

The roots are :

$\qquad \sf  \dashrightarrow \: u = \dfrac{ - b \pm \sqrt{ d } }{2a}$

$\qquad \sf  \dashrightarrow \: u = \dfrac{ - 16\pm \sqrt{ 240 } }{2 \times 4}$

$\qquad \sf  \dashrightarrow \: u = \dfrac{ - 16\pm 4\sqrt{ 15 } }{8}$

$\qquad \sf  \dashrightarrow \: u = \dfrac{ 4(- 4\pm \sqrt{ 15 }) }{8}$

$\qquad \sf  \dashrightarrow \: u = \dfrac{ - 4\pm \sqrt{ 15 } }{2}$

So, the required roots are :

$\qquad \sf  \dashrightarrow \: u = \dfrac{ - 4 - \sqrt{ 15 } }{2} \: \: and \: \: \dfrac{ - 4 + \sqrt{15} }{2}$