The volume of the aqueous solution of sodium sulfate required is 153.85 mL.
Number of moles of the salt
The number of moles of the salt in the given mass is calculated as follows;
moles = reacting mass / molar mass
molar mass of sodium sulfate = 142 g/mole
moles = (4.27) / (142)
moles = 0.03 mole
Volume of the aqueous solution of sodium sulfate
Concentration = moles/volume in liters
0.195 = 0.03/V
V = 0.03/0.195
V = 0.15385 liters
V = 153.85 mL
Thus, the volume of the aqueous solution of sodium sulfate required is 153.85 mL.
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