The isotope 131i (iodine-131), which has a half-life of 8. 02 days, is used in nuclear medical imaging. what percentage of the original activity in the sample remains after 17. 5 days?

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02-08-2022
Chemistry

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The isotope 131i (iodine-131), which has a half-life of 8. 02 days, is used in nuclear medical imaging. what percentage of the original activity in the sample remains after 17. 5 days?

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adioabiola adioabiola · Answer 1 · 2022-08-03T18:31:54+02:00

The percentage of the original sample which would remain after 17.5 days according to the given half-life of the isotope is; 22.06%.

What percentage of the original activity in the sample remains after 17.5 days?

The given sample in discuss has a half life of; 8.02 days, this therefore indicates that after 17.5 days, the number of half-life periods completed is; 17.5/8.02 = 2.18 half-lifes.

Hence, the percentage of the original sample remaining after 17.5 days can be evaluated as follows;

N = 100% × (0.5)^2.18

N = 100 × 0.22

N = 22.06%.