Question

Balance the equation for a half-reaction that occurs in acidic solution. use e− as the symbol for an electron. equation: p_{4} -> h_{3}po_{4} p4⟶h3po4

Answer 1

The balance the equation for a half-reaction that occurs in acidic solution is given as,

$P_{4}+16H_{2} O+20e^{-}$ → $4H_{3}PO_{4}+20H^{+}$

The half-reaction method to balance redox reactions in acidic aqueous solutions follows rule.

• Balance elements in the equation other than O and H.
• Balance the oxygen atoms by adding the appropriate number of water opposite side of the equation.
• Balance the hydrogen atoms by adding proton ions ( $H^{+}$ ion) to the opposite side of the equation
• Add up charge on each side of the equation by adding enough number of electrons to more positive side.
• The $e^{-}$ on each side must be equal . Multiply by appropriate integers if they are nit equal.
• The half -equation are added together, by cancelling out the electrons to form one balanced equation.

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