Question

Consider formula a to be v = startfraction 2 pi r over t endfraction and formula b to be v2 = gv = g startfraction m subscript central over r endfraction.. write the letter of the appropriate formula to use in each scenario. determine the tangential speed of the moon given the mass of earth and the distance from earth to the moon. determine the tangential speed of a satellite that takes 90 minutes to complete an orbit 150 km above earth’s surface.

Answer 1

The tangential speed of the satellite above the Earth's surface is $7.588 * 10^{3} m/s$.

What is Tangential speed?

• Tangential speed is the linear component of speed along any point on a circle that is involved in a circular motion.
• The object or circle moves with a constant linear speed at any point along the circle.
• This is known as the tangential speed.
• $v=wr\\v=\frac{2\pi r}{T}$

The tangential speed of a satellite at the given radius and time is calculated as follows:

$v=\frac{2\pi *(150*10^{3}+6371*10^{3} }{90*60} \\v=7.588*10^{3} m/s$

Therefore, the tangential speed of the satellite above the Earth's surface is $7.588 * 10^{3} m/s$.

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The correct question is shown below:
Consider formula A to be v = and formula B to be v2 = G. Write the letter of the appropriate formula to use in each scenario. Determine the tangential speed of the moon given the mass of Earth and the distance from Earth to the moon. Determine the tangential speed of a satellite that takes 90 minutes to complete an orbit 150 km above Earth’s surface.