The final velocity of the ball is 20.8 m/s. Option C
Now we have the equation;
v^2 = u^2 + 2gh
v = final velocity
u = initial velocity
a = acceleration
s = distance
v^2 = (11.4)^2 + (2 * 10 * 15.5)
v^2 = 129.96 + 310
v = √ 129.96 + 310
v = 20.8 m/s
b)
Given that;
R = u^2sin2θ/g
Where;
g = acceleration due to gravity
θ = acute angle
u = velocity
R = (60)^2 sin2(30)/10
R = 310 m
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