1.96 minutes long should it take to bring 0. 7 l of water from room temperature (20°c) to 80°c.
To find the answer, we have to know about the heat energy.
[tex]Power,P=1500W\\Volumw, V=0.7L\\T_1=20^0C \\T_2=80^0C[/tex]
[tex]m=\rho V=1kg/L*0.7L=0.7kg[/tex]
[tex]Q=mc\Delta T=0.7*4182(80-20)\\Q=1.76*10^5J[/tex]
where, c equals to 4182J/kg°C.
[tex]t=\frac{E}{P} =\frac{1.76*10^5}{1500} =117.3s=1.96minutes.[/tex]
Thus, we can conclude that, 1.96 minutes long should it take to bring 0. 7 l of water from room temperature (20°c) to 80°c.
Learn more about heat energy here:
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