Question

A 26-meter-tall statue of buddha in tibet is covered with
279 kg of gold. if the gold was applied to a thickness of
0.0015 mm, what surface area is covered in square
meters)? (gold density = 19.3 g/cm)

Answer 1

0.014559 g/cm³ is the surface area that covered in square.

Definition of surface area -

• To recall, the surface area of an object is the total area of the outside surfaces of the three-dimensional object i.e, the total sum of the area of the faces of the object. It is measured in terms of square units.
• The amount of area covered by the surface of something. The lake has roughly the same surface area as 10 football fields.

The surface area is calculated as -

Conversion of units -

$26 m * \frac{100 cm}{1 m} = 2600 cm$

$279 kg * \frac{1g}{1000 kg} = 0.279 g$

$0.0015 mm * \frac{0.1 cm}{1mm} = 0.00015 cm$

Now we use formula for volume -

      $Volume = \frac{mass}{density}$

                   $= \frac{0.279 g}{19.3 g/ cm^{3} }$

                  = 0.014559 g/cm³

Learn more about surface area

brainly.com/question/27847638

#SPJ4