A student weighs out 0. 0422 g of magnesium metal. The magnesium metal is reacted with excess hydrochloric acid to produce hydrogen gas. A sample of hydrogen gas is collected over water in a eudiometer at 32. 0°c. The volume of collected gas is 43. 9 ml and the atmospheric pressure is 832 mmhg. Using the experimentally collected data, calculate r and the percent error.

The student weighs out 0.0422 grams of the metal magnesium, thus we can figure that the more's, the magnesium he used, is the mass of the magnesium over the more mass, which is 0.024422.
That is approximately 0.001758.
Furthermore, it claims that too much hydrochloric acid causes the metal magnesium to react, producing hydrogen gas.
The volume of collected gas is 43.9 cc, the mastic pressure is 22 cc, and a sample of hydrogen gas is collected over water in a meter.

Consequently, we are aware that magnesium and chloride react.
We create 1 as the reaction ratio is 1:2.
The hydrogen and 1 are more.
Magnesium chloride is more.
Therefore, based on this equation, we can infer that the amount of hydrogen that would be created in this scenario is greater than the amount of magnesium present here, or 0.001758 more.
Among hydrogen, there is.
\Once we convert the temperature from 32 Celsius to kelvin, we can tell you that the temperature is actually about 5.15 kelvin.
The gas has a volume of 43 in m, which is equal to 0.0439 liter and indicates that the pressure is approximately 832 millimeter.
Mercury, which is 2 times 13332 plus ca, or roughly 110922.24 par, is a mathematical constant.
So, in this instance, we are aware that p v = n r t.
The r in this case equals p v over n t, thus we want to determine the r.
So p is 110922.24. The temperature is 305.15 and the V is 0.04 over the n is 0.001758.
Let's proceed with the calculations right now.
In this instance, you will discover that the solution is 9.077 times 10; that is all there is to it.

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