Question

Calculate [hy3−] in a solution prepared by mixing 10. 00 ml of 0. 0305 m voso4, 9. 20 ml of 0. 0305 m edta, and 10. 00 ml of buffer with a ph of 4. 0

Answer 1

The concentration of [ Hy³] = 4.861 *28⁻²³

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or answer. A focused answer is one which has a exceedingly massive quantity of dissolved solute. A dilute answer is one that has a tremendously small amount of dissolved solute.

Given,

 Molarity of VoSo4 ,M = 0.02M

     Vol of VoSo4 , V = 10 ml

Molarity of EDTA = 0.02 M

vol of EDTA = 9.10 ml = 0.0091 L

& 10 ml of buffer with pH =4

NOW,

     no. of moles of EDTA = molarity * Volume (L)

                                         =  0.02 M * 0.0091 L

                                        = 182 * 10^-6 moles

                                        = 1.82 * 10^-4 moles

Now,

       ∝ Y^3- = $\frac{[Y^3-]}{moles of edta}$

         [ Y^3-] = ∝ Y^3- * moles of EDTA

Given,

at pH = 4,   ∝ Y^3- = 3*10^-9

    ∴ ∝ Y^3- =  3*10^-9

        [ Y^3-] = 3*10^-9 * 1.82 * 10^-4

                   = 5.46 * 10^-13

Now, K f = [H2Y^2-]/[vo^2+][y3-]

           [vo^2+] = 18.7

[H2Y2-] = K f * [ v o+][Y^2-]

    [H2Y2] = 3.762 * 10^-13

 [ HY^3-] = 4.8 * 10^-23

So, the concentration of the    [ HY^3-] is 4.8 * 10^-23

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