Question

An atomic nucleus has a charge of 40e. an electron is 10-9 m from the nucleus. what is the force on the electron?

Answer 1

The force on the electron is (F)= 9.2 nN.

How can we calculate the value of the force on the electron?

To calculate the value of the force on the electron here we use the formula,

$F=k\frac{q_{1} q_{2} }{r^{2} }$

Here we are given,

$q_{1}$= The charge of an atomic nucleus= 40e = $40 \times 1.6 \times 10^{-19}$ C.

$q_{2}$= The charge of an electron = $1.6 \times 10^{-19}$ C.

r= The distance between the nucleus and the electron = $10^{-9}$ m.

k= The Coulomb's constant = $8.99 \times10^9 N m ^2 /C^ 2$

We have to find the value of the of the force on the electron = F

Now , we substitute the known values in the above equation, we can get

$F=k\frac{q_{1} q_{2} }{r^{2} }$

Or, $F=8.99\times 10^{9} \frac{40\times 1.6\times 10^{-19} \times 1.6\times 10^{-19} }{(10^{-9})^{2} }$

Or,$F=8.99\times 10^{9}\times {40\times (1.6\times 10^{-19} )^2\times (10^{9})^{2} }$

Or, $F= 9.2 \times 10^{-9} N$

Or, F= 9.2nN

So, from the above calculation we can conclude that the amount of force applied on the electron is 9.2nN.

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