Question

When a piece of paper is held with one face perpendicular to a uniform electric field the flux through it is 25 n·m2/c. when the paper is turned 25° with respect to the field the flux through it is:_____.

Answer 1

The flux through the paper when the paper is turned 25° with respect to field will be 22.67 $Nm^{2} /C$.

We have a piece of paper is held with one face perpendicular to a uniform electric field the flux through it is 25 $Nm^{2} /C$.

Now we have to calculate the flux through the paper if it is turned 25° with respect to the field.

What do you mean by Electric flux? What is the formula to calculate it?

Electric flux (E) through a surface is defined as the dot product of Electric field vector and Normal vector to the surface. The formula to calculate the electric flux is -

Φ = $\vec{E}.\vec{A}$ = E x A x cosθ

In the question it is given that when one face perpendicular to a uniform electric field the flux through it is 25 $Nm^{2} /C$. In this case θ = $0^{o}$.

Therefore -

E x A x cos $0^{o}$ = 25

EA = 25 $Nm^{2} /C$

When the paper is turned $25^{o}$ with respect to field, then the flux through it can be calculated as follows -

Φ = 25 x cos ($25^{o}$) = 22.67 $Nm^{2} /C$.

Hence, the flux through the paper will be 22.67 $Nm^{2} /C$.

To solve more question on Electric flux , visit the link below -

https://brainly.com/question/14527109

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