Combining of the two cylinders gives a composite figure that has the surface area of a solid cylinder of radius 7 mm and height 6 mm, such that the surface area of the figure is approximately 571.5 mm².
Which method can be used to find the surface area of the figure?
Radius of the inner cylinder, r = 3 mm
Radius of the outer cylinder, R = 7 mm
Height of the cylinders, h = 6 mm
Given that the inner cylinder exactly fits into the outer cylinder, we have;
The surface area of the composite figure is the surface area of the hollow outer cylinder + The area of the top and bottom of the inner cylinder.
Which gives;
The surface area of the composite figure, A, is the surface area of a solid cylinder, using the dimensions of the hollow outer cylinder.
Which gives;
- A = 2 × π × 7² + 2 × π × 7 × 6
Where, π = 3.14, we have;
A = 2 × 3.14 × 7² + 2 × 3.14 × 7 × 6 ≈ 571.5
- The surface area of the composite figure, A ≈ 571.5 mm²
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