Mycobacterium tuberculosis is known for surviving in the phagolysosome to avoid host cell detection. Thus, option B is correct.
A phagolysosome is a type of cytoplasmic body which is an union of phagosome and a lysosome. The interior is highly acidic and contain hydrolytic enzymes.
These enzymes digest and destroy the harmful microorganisms.
The mechanism of formation of Phagolysosome by phagocytosis is an immunological functions.
Although phagolysosome and phagosomes are membrane bound vesicles, primary difference is that phagolysosome is formed by the fusion of a phagosome with a lysosome where as phagosome is formed around the particles engulfed by a phagocytic cell.
Hence, option B is correct.
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Your question was incomplete. Hence the probable question was
Which microorganism is known for surviving in the phagolysosome to avoid host cell detection?
A. Escherichia coli
B. Mycobacterium tuberculosis
C. Mycoplasma sp.
D. micrococcus luteus