Question

The probability that a rental car will be stolen is. 4. if 3500 cars are rented, what is the approximate poisson probability that 2 or fewer will be stolen?

Answer 1

Using the Poisson distribution, there is a 0.8335 = 83.35% probability that 2 or fewer will be stolen.

What is the Poisson distribution?

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

• x is the number of successes

• e = 2.71828 is the Euler number

• $\mu$ is the mean in the given interval.

The probability that a rental car will be stolen is 0.0004, hence, for 3500 cars, the mean is:

$\mu = 3500 \times 0.0004 = 1.4$

The probability that 2 or fewer cars will be stolen is:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

In which:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.4}1.4^{0}}{(0)!} = 0.2466$

$P(X = 1) = \frac{e^{-1.4}1.4^{1}}{(1)!} = 0.3452$

$P(X = 2) = \frac{e^{-1.4}1.4^{2}}{(2)!} = 0.2417$

Then:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2466 + 0.3452 + 0.2417 = 0.8335$

0.8335 = 83.35% probability that 2 or fewer will be stolen.

More can be learned about the Poisson distribution at https://brainly.com/question/13971530

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