Question

If 30. 0 ml of 0. 150 m CaCl2 is added to 15. 0 ml of 0. 100 m AgNo3, what is the mass in grams of AgCl precipitate?

Answer 1

The mass of AgCl precipitated is 0.215g.

What do you mean by  precipitation?

Precipitate is to form an insoluble compound either by reacting two salts or by changing the temperature to affect the solubility of the compound.

To calculate mass of AgCl precipitate -

The first step is to make a balanced chemical equation.

2AgNO3 + CaCl2 ---> 2AgCl + Ca(NO3)2

Molecular Weights:

CaCl2 = 110.98 g/mol

AgNO3 =170.01g/mol

AgCl= 143.45 g/mol

Volume:

CaCl2: 30.0mL=0.03L

AgNO3: 15.0mL=0.015 L

mole  CaCl2 = 30/1000 x 0.2 =0.006

mole  AgNO3 =15/1000 x 0.1 = 0.0015

CaCl2 is in excess so 0.0015 mole AgCl  will form

0.0015 x 143.5 = 0.215g

The 0.215 mass in grams of AgCl will precipitate.

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