Respuesta :
The molality of a solution containing 3. 0 moles of NaCl and 100. 0 moles of water is 30 mol/kg.
The number of moles of solute in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality. Mole per kilogram of solvent is the SI unit for molality.
Given:
3.0 moles of NaCl in 100 moles of water.
To find:
The molality of the solution
The moles of solute (NaCl) = 3.0 moles
The mass of solvent (water) = 100 moles (0.1 kg/mol)
Molality of a solution = Number of Moles of solute/ Mass of solvent(kg)
= 3.0 moles/0.1 kg/mol
= 30 mol/kg
To know more about Molality refer:
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