Question

The density of lithium is 0. 546 g/cm3. what volume is occupied by 3. 66 x 10 23 atoms of lithium?

Answer 1

The volume occupied by 3.66 x $10^{23}$ atoms of lithium is 7.73 $cm^3$

What is Density?

The density of a substance is defined as the mass of the substance per unit volume. It is often denoted by the symbol ρ

The density of a substance is given by,

$\rho = \frac{m}{V}$

The mass of a substance is the measure of the amount of matter present in it. It is generally measured in grams (g) or kilograms (kg).

The volume of a substance is defined as the amount of 3D space occupied by it.

What is Mole Concept?

It is a concept which uses mole as a unit to measure the number of atoms, molecules or ions.

A mole is defined as the amount of substance which has the same number of elementary particles as there are atoms in 12 grams of $\ce{^{12}C}$

1 mole = Avogadro's number = 6.022 x $10^{23$ atoms

Steps to find out the volume

Molar Mass of Lithium = 6.94 g/mol

1 mole of Lithium has 6.022 x $10^{23}$ atoms

3.66 x $10^{23}$ atoms of lithium has molar mass = $\frac{6.94 g}{6.022\times10^{23} } \times 3.66 \times 10^{23}$

$m = 4.218 g$

Substitute in density formula,

$\rho = \frac{m}{V}$

$V = \frac{m}{\rho}$

$=\frac{4.218g}{0.546g/cm^3}$

= 7.73 $cm^3$

Therefore, 3.66 x $10^{23}$ atoms of lithium occupies 7.73 $cm^3$ of volume.

Learn more about the mole concept:

https://brainly.com/question/1427235

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