Question

A doubly charged ion with velocity 6. 9 × 106 m/s moves in a path of radius 30 cm in a magnetic field of 0. 80 t in a mass spectrometer. what is the mass of this ion?

Answer 1

The mass of this ion is 1.16*10^-26kg.

To find the answer, we have to know about the force acting on a particle circulating in a uniform magnetic field.

How to find the mass of this ion?

• Let us consider that, a particle of mass m with charge q moving with velocity v in a circular orbit of radius r, then the centripetal force of it's path will be equal to the Lorentz magnetic force.

                                  $F_c=F_B\\\frac{mv^2}{r} =qvB$

• Thus, the mass of the doubly charged ion will be,

                   $m=\frac{qBr}{v} =\frac{2*1.67*10^{-19}*0.8*30*10^{-2}}{6.9*10^6} \\m=1.16*10^{-26}kg$

Thus, we can conclude that, the mass of this ion is 1.16*10^-26kg.

Learn more about the force here:

https://brainly.com/question/11701736

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