The set of irrational numbers exists not closed under addition exists π+π = 2π.
A set exists closed under a given operation if all possible values in the set would have the exact type of number when the operation exists completed.
Irrational numbers exist not closed under addition because:
π+(-π) would be zero.
π and (-π) exist as irrational.
However zero exists not irrational.
Therefore, the set exists not closed.
Therefore, the correct answer is option c. π+π = 2π
For example: The square root of 5 plus the square root of 5 exists two square roots of 5.
Both numbers exist irrational and they produce an irrational result.
Therefore, the correct answer is option c. π+π = 2π
To learn more about irrational numbers refer to:
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