Question

Burning 2.00 mol of hydrogen releases 483.6 kJ of energy. Determine how much energy, in kilojoules, must be supplied to convert 3.00 mol of water vapor into hydrogen gas and oxygen gas.

Express your answer with the appropriate units.

Answer 1

The amount of heat energy (in KJ) needed to convert 3 moles of water vapor into hydrogen gas and oxygen gas is 1450.8 KJ

Balanced equation

We'll begin by writing the balanced equation. This is illustrated below:

2H₂ + O₂ --> 2H₂O ΔH = 483.6 KJ

From the balanced equation above,

2 moles of water (H₂O) required 483.6 KJ to produce hydrogen gas and oxygen gas

How to determine the heat energy needed to convert 3 moles of water to hydrogen gas and oxygen gas

The heat energy needed to convert 3 moles of water can be obtained as illustrated below:

From the balanced equation above,

2 moles of water (H₂O) required 483.6 KJ to produce hydrogen gas and oxygen gas

Therefore,

3 moles of water (H₂O) will require = 3 × 483.6 = 1450.8 KJ to produce hydrogen gas and oxygen gas

Thus, we can conclude that the energy needed to convert 3 moles of water is 1450.8 KJ

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