Find the orbital speed of an ice cube in the rings of Saturn. The mass of Saturn is 5.68 x 1026 kg, and use an orbital radius of 3.00 x 105 km. (G = 6.67 × 10-11 N ∙ m2/kg2)

Respuesta :

The orbital speed of an ice cube in the rings of Saturn is determined as  11,237.7 m/s.

What is orbital speed?

The orbital speed of an astronomical body or object is the speed at which it orbits around the center of mass of the most massive body.

Orbital speed of ice cube in the rings of Saturn

The orbital speed of ice cube in the rings of Saturn is calculated as follows;

v = √GM/r

where;

  • G is universal gravitation constant
  • M is mass of Saturn
  • r is the distance of the ice cube = 3 x 10⁸ m

v = √(6.67 x 10⁻¹¹ x 5.68 x 10²⁶)/(3 x 10⁸)

v = 11,237.7 m/s

Thus, the orbital speed of an ice cube in the rings of Saturn is determined as  11,237.7 m/s.

Learn more about orbital speed here: brainly.com/question/22247460

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