Question

What is the simplified form of the quantity of x plus 6, all over the quantity of x plus 4 + the quantity of x minus 3, all over 3 ? (2 points) the quantity of x squared plus 3x minus 18, all over 3 times the quantity of x plus 4 the quantity of x squared plus 4x plus 6, all over the quantity of x plus 7 the quantity of x squared plus 3x minus 18, all over the quantity x plus 7 the quantity of x squared plus 4x plus 6, all over 3 times the quantity of x plus 4

Answer 1

The simplified expression of the given equation is  $\frac{x^{2} + 4x + 6}{3x + 12}$

There are three basic steps for addition or subtraction of two fractions

• Step 1: Make sure the bottom numbers (the denominators) are the same
• Step 2: Add the top numbers (the numerators), put that answer over the denominator
• Step 3: Simplify the fraction (if possible)

The given expression :- $\frac{x+6}{x+4} +\frac{x-3}{3}$

Taking LCM or making the denominators same we get,

= {3(x+6) + (x-3)(x+4)}/3(x+4)

= {3x + 18 + x² +x -12}/3(x+4)

={x² + 4x + 6}/3x + 12

= $\frac{x^{2} + 4x + 6}{3x + 12}$

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