Question

Let f(x) = cxe−x2 if x ≥ 0 and f(x) = 0 if x < 0. For what value of c is f a probability density function? for that value of c find P(1

Answer 1

The value of c such that the function f is a probability density function is 2

How to determine the value of c?

The density function is given as:

f(x) = cxe^(−x^2) if x ≥ 0

f(x) = 0 if x < 0.

We start by integrating the function f(x)

∫f(x) = 1

This gives

∫ cxe^(−x^2) = 1

Next, we integrate the function using a graphing calculator.

From the graphing calculator, we have:

c/2 * (0 + 1) = 1

Evaluate the sum

c/2 * 1 = 1

Evaluate the product

c/2 = 1

Multiply both sides of the equation by 2

c = 2

Hence, the value of c such that the function f is a probability density function is 2

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