Question

What is the specific heat of a substance if 1500 J are required to raise the temperature of a 300.0 g sample from 25°C to 40°C?
Group of answer choices

A. 33 J/g°C

B. 333 J/g°C

C. 4.18 J/g°C

D. .33 J/g°C

Answer 1

Answer:

D.) 0.33 J/g°C

Explanation:

To find the specific heat, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

You can plug the given values into the equation and simplify to isolate "c".

Q = mcΔT                                                   <----- Equation

1500 J = (300.0 g)c(40 °C - 25°C)             <----- Insert values

1500 J = (300.0 g)c(15)                              <----- Subtract

1500 J = (4500)c                                        <----- Multiply 300.0 and 15

0.33 = c                                                      <----- Divide both sides by 4500