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(geometry involving arc lengths)

In geometry, the length of JK in terms of a, b, and x will be D. abx
It should be noted that from the information given, it was stated that in circle M, EMF measures the radians allocated, the length of radius FM is and the length of EF is x.
In the other circle, JNK also measures the radians allocated and the length of radius KN is b.
Therefore, the length of JK in terms of a, b, and x will be:
= a × b × x
= abx
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Answer:
bx/a (3rd choice)
Step-by-step explanation:
The length of an arc, s, in a circle of radius r, and central angle Θ given in radians is
s = rΘ
Circle M has radius a. The central angle in radians of the sector is Θ. The length of the arc is x.
x = aΘ
Solve for Θ:
Θ = x/a Eq. 1
Circle N has radius b. The central angle in radians of the sector is Θ. The length of the arc is s.
s = bΘ
Solve for Θ:
Θ = s/b Eq. 2
Since Θ = Θ, then equate the right sides of Equations 1 and 2 above.
x/a = s/b
Multiply both sides by ab.
abx/a = abs/b
bx = as
as = bx
s = bx/a
Answer: bx/a