Based on the positive-going zero crossing at 0° of the sine wave, the instantaneous value at 15° is 7.321V.
What is the instantaneous value?
At 15°, the instantaneous value is:
= 20√2 x Sin(angle)
Solving gives:
= 20√2 x Sin(15°)
= 7.321V
At angel 33°, the instantaneous value is:
= 20√2 x Sin(angle)
= 20√2 x Sin(33)
= 15.405V
At angle 70°:
= 20√2 x Sin(angle)
= 20√2 x Sin(70)
= 26.579V
The full question is:
A certain sine wave has a positive-going zero crossing at 0° and an rms value of 20 V. Calculate its instantaneous value at each of the following angles: a. 15° b. 33° c. 70°
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