Question

How many joules are given off when 120 grams of water are cooled from 0C to -25C?

Answer 1

Answer:

46 359 J

Explanation:

You need heat of fusion of water:   334 J/g

 and specific heat of ice : 2.093 j/g-C

120 * 334    = 40 080 J to make ice

+   120 * 2.093 * 25  = 6279 J   to chill the ice to -25 C

Total = = 46359 J