Question

two candles of the same height are lighted at the same time. the first is consumed in 4 hrs and the second in 3 hrs. assuming that each candle burns at a constant rate, in how many hours after being lighted was the first candle twice the height of the second?

Answer 1

The height of candle 4 is twice that of candle B after 2.4 hours.

How many hours after being lighted was the first candle twice the height of the second?

For candle, A time is taken for 100% bearning=4hour.

For 1 hour, it burns for 25%(100/4)

After 1 hr.$\frac{25}{100}$

After x hours, the amount burnt$=\frac{x}{4}$

Amount left$=1-\frac{x}{4} =\frac{4-x}{4}$

Let's not presume that candle B's height will be half that of candle A after x hours.

After x hours, part vemacing $=1-\frac{x}{3} =\frac{3-x}{3}$

$\frac{4-x}{4} =1\frac{3-x}{3}$

Height of candle A$=2$×Height of candle B.

$12-3x=24-8x$

   ⇒$5x=12$

        $x=\frac{12}{5}$

           $=2.4$

The height of candle 4 is twice that of candle B after 2.4 hours.

To learn more about the candles of equal height, refer to:

https://brainly.com/question/15493665

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