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The answer is J.
The probability of spinning B on Spinner 1 is equal to the ratio of number of B to the total number of letter spaces.
The probability of spinning 1 on Spinner 2 is equal to the ratio of number of 1 to the total number of number spaces.
The probability is equal to :
Answer:
J [tex]\frac{1}{12}[/tex]
Step-by-step explanation:
• First, let's find the probability of landing a letter B in Spinner 1.
We have a total of eight possibilities, and two of them are the letter B.
∴ [tex]P(B) = \frac{2}{8}[/tex]
= [tex]\bf \frac{1}{4}[/tex]
• Next, let's find the the probability of landing the number 1 on Spinner 2.
There are a total of six possibilities, and two of them are the number 1.
∴ [tex]P(1) = \frac{2}{6}[/tex]
= [tex]\bf \frac{1}{3}[/tex]
• Now we have to calculate the probability of spinning a letter B and the number 1:
[tex]P(B \space\ and\space\ 1) = \frac{1}{4} \times \frac{1}{3}[/tex]
= [tex]\bf \frac{1}{12}[/tex]