Answer:
13. x^2 + y^2 = 3
14. B
Step-by-step explanation:
13. Since it's centered at the origin, (0, 0), the values of h and k in (x - h)^2 + (y - k)^2 = r^2 are equal to zero. So we simply have x^2 + y^2, and since the radius is the square root of 3, squaring the radius gives us 3.
14. B is the only circle with both a radius of 3 that's also shifted to the right 1 and down 2, since it's centered at (h, k), which is (1, -2).
Hope this helps! Brainliest, please :)
