The angles and side lengths for both triangles are;
3) A = 36°; B = 54°; C = 90°; a = 7; b = 9.63; c = 4.11
4) A = 64°; B = 26°; C = 90°; a = 1.798; b = 0.88; c = 2
How to solve Pythagoras theorem?
3) From the diagram, we are already given;
B = 54°
C = 90°
a = 7
We know that sum of angles in a triangle is 180° and so;
A = 180 - (90 + 54)
A = 36°
By trigonometric ratios;
b/7 = tan 54
b = 7 * tan 54
b = 7 * 1.376
b = 9.63
7/c = cos 54
c = 7 * cos 54
c = 4.11
4) From the diagram, we are already given;
B = 26°
C = 90°
c = 2
We know that sum of angles in a triangle is 180° and so;
A = 180 - (90 + 26)
A = 64°
By trigonometric ratios;
b/2 = sin 26
b = 2 * sin 26
b = 2 * 0.4384
b = 0.88
a/2 = cos 26
a = 2 * cos 26
a = 1.798
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