Question

The point-slope form of the equation of the line that passes through (–9, –2) and (1, 3) is y – 3 = one-half EndFraction(x – 1). What is the slope-intercept form of the equation for this line?

y = y equals StartFraction one-half EndFraction x plus 2.x + 2
y = y equals StartFraction one-half EndFraction x minus 4.x – 4
y = y equals StartFraction one-half EndFraction x plus StartFraction 5 Over 2 EndFraction.x +
y = y equals StartFraction one-half EndFraction x minus StartFraction 7 Over 2 EndFraction.x –

Answer 1

The slope-intercept form of given equation is y = 1/2x + 5/2.

According to the statement

we have given that the equation y-3 = 1/2(x-1) and the passing points are (–9, –2) and (1, 3).

And we have to find the slope-intercept form of the equation

slope-intercept form is the equation of a straight line in the form y = mx + b where m is the slope of the line and b is its y-intercept.

So, According to this

y-3 = 1/2(x-1)

convert this into y = mx +b form then

y-3 = 1/2x -1/2

here m is 1/2 and b is -1/2.

Then

y-3 = 1/2x -1/2

Add three on both sides then

y = 1/2x + 5/2

So, The slope-intercept form of given equation is y = 1/2x + 5/2.

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