Determine if the following infinite series converges or diverges

Using limits, it is found that the infinite sequence converges, as the limit does not go to infinity.
Suppose an infinity sequence defined by:
[tex]\sum_{k = 0}^{\infty} f(k)[/tex]
Then we have to calculate the following limit:
[tex]\lim_{k \rightarrow \infty} f(k)[/tex]
If the limit goes to infinity, the sequence diverges, otherwise it converges.
In this problem, the function that defines the sequence is:
[tex]f(k) = \frac{k^3}{k^4 + 10}[/tex]
Hence the limit is:
[tex]\lim_{k \rightarrow \infty} f(k) = \lim_{k \rightarrow \infty} \frac{k^3}{k^4 + 10} = \lim_{k \rightarrow \infty} \frac{k^3}{k^4} = \lim_{k \rightarrow \infty} \frac{1}{k} = \frac{1}{\infty} = 0[/tex]
Hence, the infinite sequence converges, as the limit does not go to infinity.
More can be learned about convergent sequences at https://brainly.com/question/6635869
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The series diverges by the comparison test.
We have for large enough [tex]k[/tex],
[tex]\displaystyle \frac{k^3}{k^4+10} \approx \frac{k^3}{k^4} = \frac1k[/tex]
so that
[tex]\displaystyle \sum_{k=0}^\infty \frac{k^3}{k^4+10} = \frac1{10} + \sum_{k=1}^\infty \frac{k^3}{k^4+10} \approx \frac1{10} + \sum_{k=1}^\infty \frac1k[/tex]
and the latter sum is the divergent harmonic series.