The probability of obtaining a success is 0.010935.
Given that the probability of obtaining success is P(X>=5),n=6,p=0.3.
We are required to find the probability of obtaining a success if the probability is P(X>=5).
Probability is basically likeliness of happening an event among all the events possible.
Binomial distribution is basically the discrete probability distribution of the number of successes in a sequence of n independent experiments.
[tex](a+b)^{n} =nC_{0}p^{0} (1-p)^{n-0}+-----------nC_{n} p^{n} (1-p)^{0}[/tex]
We have to just put n=6 anr r=6 and 5 one by one to get the probability.
P(X>=5)=[tex]6C_{5}(0.3)^{5} (0.7)^{1} +6C_{6}(0.3)^{6} (0.7)^{0}[/tex]
=6!/5!1!8*0.00243*0.7+0.000729
=6*0.00243*0.7+0.000729
=0.010206+0.000729
=0.010935
Hence the probability of obtaining a success if the probability is P(X>=5) is 0.010935.
Learn more about probability at https://brainly.com/question/24756209
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