Question

A school dance committee has 14 volunteers. Each dance requires 3 volunteers at the door, 5 volunteers on the floor, and 6 floaters. If two of the volunteers, Christine and Samuel, cannot work together since they are new, in in how many ways can the volunteers be assigned?

Answer 1

There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.

Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.

We are required to find the number of ways in which the volunteers can be assigned.

Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.

n$C_{r}$=n!/r!(n-r)!

Number of ways in which the volunteers can be assigned is equal to the following:

Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.

Number of ways =14$C_{12}$

=14!/12!(14-12)!

=14!/12!*2!

=14*13/2*1

=91 ways

Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.

Learn more about combinations at https://brainly.com/question/11732255

#SPJ1