Question

There are 8 players on a tennis team. The team is planning to play in a doubles tournament. How many different groups of players of 2 players can the coach make, if the position does not matter?

28
64
20,160
40,320

Answer 1

Using the arrangements formula, it is found that there are 20,160 different groups of players of 2 players that the coach can make.

What is the arrangements formula?

The number of possible arrangements of n elements is given by the factorial of n, that is:

$A_n = n!$

In this problem, all 8 players will play, hence considering the order, the number of ways is:

$A_8 = 8! = 40320$

However, the position does not matter, as for example, João and Elisa would form the same pair as Elisa and João, hence the removing the order, the number of groups is:

40,320/2 = 20,160.

More can be learned about the arrangements formula at https://brainly.com/question/24648661

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