Question

A 1300 kg sports car can accelerate from 0 to 27 m/s in 5.2 seconds. How much power from the engine is directly going into accelerating the car? Group of answer choices 474,000 W 3375 W 35,100 W 91,100 W

Answer 1

The power expended is calculated as 91,100 W.

What is the power?

We know that the acceleration can be obtained by the use of the equation;

v = u + at

v = final velocity

u = initial velocity

t = time

a = acceleration

a= v - u/t

a =  27 - 0/ 5.2 = 5.2 m/s^2

Thus;

v^2 = u^2 + 2as

but u= 0 m/s

v^2 = 2as

s =  v^2/2a

s = (27)^2/2 * 5.2

s = 70 m

Now;

Work done =  1300 kg * 5.2 m/s^2 * 70 m = 473200 J

Power = 473200 J/5.2 seconds

Power =  91,100 W

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