Question

If 1.240g of carbon dioxide dissolves in 1.01L of water at 755mmHg, what quantity of carbon dioxide in grams will dissolve at 790mmHg?

Answer 1

Taking into account the Henry's Law, 1.297 g carbon dioxide will dissolve at 790 mm Hg in 1.01 L water.

Henry's Law

A change in pressure does not appreciably influence the solubility of solids or liquids or liquids in liquids; however, that of gases in solvents increases when the partial pressure of the gases increases. The solubility of a gas depends on pressure and temperature.

In this way, Henry's Law describes the effect of pressure on the solubility of gases. This law states that the solubility of a gas in contact with the surface of a liquid at a given temperature is directly proportional to the partial pressure of said gas on the liquid.

Mathematically, Henry's law is expressed as:

C=k×P

Where:

• P is the partial pressure of the gas.
• C is the concentration of the gas.
• k is Henry's constant, which depends on the nature of the gas, the temperature, and the liquid.

At 2 different partial pressure values, the Henry's law is expressed as:

$\frac{C1}{C2} =\frac{P1}{P2}$

Quantity of carbon dioxide

In this case, you know:

• C₁ = $\frac{1.240 g}{1.01 L}$ =1.228 $\frac{g}{L}$
• C₂ = ?
• P₁ = 755 mm Hg
• P₂ = 790 mm Hg

Replacing in Henry's Law:

$\frac{1.228\frac{g}{L} }{C2} =\frac{755 mmHg}{790mmHg}$

Solving:

$1.228\frac{g}{L} =\frac{755 mmHg}{790mmHg}xC2$

C2= $\frac{1.228\frac{g}{L} }{\frac{755 mmHg}{790mmHg}}$

C2= 1.285 $\frac{g}{L}$

Then, the concentration of carbon dioxide at 790 mmHg is 1.285 g/L. But you have 1.01 L of water. So the amount of gas dissolved can be calculated as 1.01 L×1.285 g/L = 1.297 g

Finally, 1.297 g carbon dioxide will dissolve at 790 mm Hg in 1.01 L water.

Learn more about Henry's Law:

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